Consider a needle of length \( L \), diameter \( d \), and mass \( m \) placed vertically on a horizontal surface, standing on its tip under normal conditions (i.e., no unusual weather disturbances, typical gravitational field of \( g = 9.81 \, m/s^2 \), etc.). The question is to determine the probability \( P \) that the needle will continue to stand on its nose after being placed this way.
We start by considering the critical angle \( \theta \) at which the needle will begin to tip over due to gravitational torque. If the needle deviates from the vertical by an angle greater than \( \theta_c \), it will no longer be able to return to the vertical position due to gravitational forces.
Using small-angle approximation, the probability \( P \) of the needle standing on its tip can be related to the critical angle and the stability dynamics.
The critical angle \( \theta_c \) at which the needle tips is given by:
\[ \theta_c \approx \arctan\left(\frac{d}{2L}\right) \]
The probability \( P \) of the needle staying balanced on its tip can be approximated using a stability argument, resulting in:
\[ P \approx e^{-\frac{mgL}{2kT}} \]
where:
Given that the probability \( P \) is exponentially small, it suggests that under typical conditions, it is highly unlikely for the needle to stay balanced on its tip. This probability decreases further as the height-to-width ratio \( \frac{L}{d} \) of the needle increases, making such an event practically impossible in real-world scenarios.